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The EML Challenge Board
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Canonical validator and leaderboard for open problems in the EML operator. Submit a construction. Get credited permanently. arXiv:2603.21852
The operator
eml(x, y) = exp(x) − ln(y)
Grammar: S → 1 | eml(S, S) · strict principal-branch ln · ln(0) undefined
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Open Challenges — 4 problems
sin(x)
OPEN
Construct sin(x) as a pure EML tree using only constant {1} under strict principal-branch ln where ln(0) throws.
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cos(x)
OPEN
Construct cos(x) as a pure EML tree using only constant {1} under strict principal-branch ln where ln(0) throws.
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π
OPEN
Construct the constant π from terminal {1} under strict principal-branch grammar.
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i (strict grammar)
OPEN
Construct i = √−1 from terminal {1} under strict principal-branch grammar. Under extended-reals convention this is solved (K=75, pveierland). Under strict grammar it remains open.
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